Destructuring in lambdas

1

Wouldn't it be nice to be able to use destructuring in lambdas?

Consider the following code, where ‘subscribe’ receives an instance of Pair (emitted by the observable):

    val subscription = AndroidObservable

           .bindActivity(this, observable)
           .subscribeOn(Schedulers.computation())
           .subscribe({ (list, theme) ->
                   adapter.setTheme(theme)
                   adapter.swapData(list)
           })

Currently Kotlin does not support this and I have to use something like

.subscribe({ data ->
  val (list,theme) = data
  //…
})

which isn’t too bad, but still I’d like it to be even better :slight_smile:

Is such kind of syntax planned for Kotlin in future or there are some conserns with it?

2 Likes
2

Yes, this feature is planned, though exact design is not finalized yet.

2 Likes
3

Nice to know, thanks! Please mention it in some blog post when it's ready ;)

4

I implemented this using extension functions:

inline fun <A,B,R> List<Pair<A,B>>.forEach( op : ((A,B) → R)) = this.forEach { op(it.first,it.second) }
inline fun <A,B,R> List<Pair<A,B>>.map( op : ((A,B) → R)) = this.map { pair → op(pair.first,pair.second) }
inline fun <A,B> List<Pair<A,B>>.filter( op : ((A,B) → Boolean)) = this.filter { pair → op(pair.first,pair.second) }

5

I wrote these extension functions a few weeks ago:

inline fun <K, V> Iterable<Map.Entry<K, V>>.forEachEntry(action: (K, V) -> Unit) =
    forEach { action(it.key, it.value) }

inline fun <A, B> Iterable<Pair<A, B>>.forEachPair(action: (A, B) -> Unit) =
    forEach { action(it.first, it.second) }
3 Likes