How do I access String.CASE_INSENSITIVE_ORDER from Kotlin?

1

I am using M3.1 with the latest IDEA 12 EAP.

I’m trying to convert a regular HashMap to a sorted map.

When I try:

  val map = HashMap<String, String>()   map.toSortedMap(String.CASE_INSENSITIVE_ORDER)

then String has the red wiggly underline and it calls String a classifier (which I don't understand).

If I try fully qualifying it:

  val map = HashMap<String, String>()   map.toSortedMap(java.lang.String.CASE_INSENSITIVE_ORDER)

then toSortedMap gets the red wiggly underline & it tells me that type inference has failed (Cannot infer type parameter K).

What is the right way to access String’s static field?

Thanks,

Neil

2

You make 50% of work :-)

In kotlin String != java String. So it is right to call java.lang.String.CASE_INSENSITIVE_ORDER

Kotlin think that all things came from java are Nullable.

val CASE_INSENSITIVE_ORDER : Comparator<String?>

But we can fix it with external annotations. Go to definition of CASE_INSENSITIVE_ORDER, and do this http://blog.jetbrains.com/kotlin/using-external-annotations/ In our case we need to set it:

val CASE_INSENSITIVE_ORDER : Comparator<String>

Working sample

val map = hashMap<String, String>(“2” to “2”, “1” to “1”, “3” to “3”)

println(map) //{3=3, 2=2, 1=1}
val sorted = map.toSortedMap(java.lang.String.CASE_INSENSITIVE_ORDER)
println(sorted) //{1=1, 2=2, 3=3}

1 Like
3

Thank you. That worked.