Should max()/maxBy()/maxWith() return the last largest element?

[ilya.gorbunov]

@acefalobi

And I wanted to get the song with the most amount of plays but also sorted by the number of songs on the album so if two albums been played the same amount of time, I would then use the number of songs on it to decide which one to return since the same amount of plays on a smaller album might indicate more preference.

If you want to get an album with the maximum number of plays and when there’s a tie, with the minimum number of songs, it would be much more easy, efficient, and reliable to construct a custom comparator:

data class Album(val noOfSongs: Int, val noOfPlays: Int)

fun main() {
//sampleStart
    val albums = listOf(Album(15, 20), Album(9, 15), Album(10, 20)).shuffled()
    val comparator = compareBy<Album> { it.noOfPlays }.thenByDescending { it.noOfSongs }
    
    println(albums.maxWith(comparator))   
//sampleEnd
}