Good afternoon, below I’ve attached source code of overloading of divide operator for BigDecimal.

@kotlin.internal.InlineOnly

public inline operator fun BigDecimal.div(other: BigDecimal):

BigDecimal = this.divide(other, RoundingMode.HALF_EVEN)

Was there any reason to use `RoundingMode.HALF_EVEN`

and `BigDecimal::divide(BigDecimal divisor, RoundingMode roundingMode)`

instead of `BigDecimal::divide(BigDecimal divisor)`

?

This is not obvious, in my opinion, as it results in `12.0 / 100.0 = 0.0`

instead of `12.0 / 100.0 = 0.12`

if using BigDecimals.

I understand, that this may lead to `ArithmeticException: “Non-terminating decimal expansion; no exact representable decimal result”`

, but in my opinion, this will be same way as for Java, and, therefore, more obvious.